A function in Typescript that dynamically determines its return type based on a specified generic parameter

Currently, I am attempting to create a function where the return type is determined by a generic argument. Let me share a code snippet to illustrate:

type ABCDE = 'a' | 'b';

function newFunc<U extends ABCDE>(input: U): U extends 'a' ? 'result1' : 'result2' {
  if (input === 'a') {
    return 'result1';
  }
  return 'result2';
}

const responseOne = newFunc('a'); // this should be of type 'result1'
const responseTwo = newFunc('b'); // this should be of type 'result2'

While inside the function, I encountered the error

Type '"result1"' is not assignable to type 'U extends "a" ? "result1" : "result2"'.
. I'm uncertain how to address this issue.

I have come across similar questions, but none specifically tackle the combination of dependent return types with union types. The closest reference I found was in this post, which suggests that it may currently be an insurmountable obstacle, though I cannot say for certain.

Answer №1

To improve type safety, you may consider using function overload:

type ABCDE = 'abc' | 'def';

function xyz(arg: 'abc'): 'result1';
function xyz(arg: 'def'): 'result2';
function xyz(arg: ABCDE) {
  if (arg === 'abc') {
    return 'result1';
  }
  return 'result2';
}

const abcResult = xyz('abc'); // this will be typed as 'result1'
const defResult = xyz('def'); // this will be typed as 'result2'

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