A guide on implementing isomorphic types in TypeScript

Consider the following scenario with two files, file.ts:

let a: Message = "foo"
let b: Message = "bar"
let c: Message = "baz"

Now let's introduce a second file, file2.ts

type Message = string

function fun(abc: Message): void { }

When using function fun, we can pass a string instead of Message due to it being a type alias. How can we create isomorphic types that behave like another type but enforce strict checks, similar to Haskell's newtype?

Answer №1

If you explore the documentation on string literal types (specifically under "String literal"), you'll find a concept similar to an enum. However, instead of choosing from a range of options, it restricts a string type to only specific values:

type Message = "apple" | "banana" | "orange";

Answer №2

One way to achieve this is through enumerating simulation.

type Item = "apple" | "banana" | "orange";
const Item = {
    Apple: 'apple' as Item,
    Banana: 'banana' as Item,
    Orange: 'orange' as Item
}

Then you can implement the following:

function itemFunction(fruit: Item): void { 
    // functionality goes here, for example 
    if (fruit === Item.Banana) {
       /// ...
    }
}
itemFunction(Item.Apple)  // works fine
itemFunction("banana")  // works fine
itemFunction("pear")  // gives an error

Answer №3

To restrict the values of the Message type to a specific set of options, you can define it like this.

type Message = "apple" | "banana" | "orange";

function welcome(message: Message) { 
    alert(message);
}

welcome("apple"); // runs successfully

welcome("not-on-the-list-will-fail"); // will throw an error

Answer №4

Here is a possible solution:

let value:Item | string | any = "bar"

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