A guide on showcasing nested arrays data in an Angular application

Question

A guide on showcasing nested arrays data in an Angular application

info = [
    {
        list: [
            { title: 'apple'}
        ]
    },
    {
        list: [
            { title: 'banana'}
        ]
    }
]

My goal here is to extract the list items. Here is how they are structured.

desired result:

info = [
    {
        title: 'apple'
    },
    {
        title: 'banana'
    }
];

This will eliminate the empty array and consolidate the data accordingly.

javascript angular typescript

Answer 1

Answer №1

Method 1:

To simplify your array, you can utilize the reduce method like so -

var data = [
    {
        rows: [
            { name: 'a'}
        ]
    },
    {
        rows: [
            { name: 'b'}
        ]
    },
    {
        rows: []
    }
]

var reducedSet = [];
data.reduce((accumulator, currentValue, currentIndex) => {
  var currentRows = currentValue.rows;
  var rowLength = currentRows && currentRows.length
  if (rowLength) {
    for (i = 0; i < rowLength; i++) {
            accumulator.push(currentRows[i]);
        }
    return accumulator;
  }
}, reducedSet);

console.log(reducedSet);

Method 2:

Alternatively, you can approach it in this way too -

var data = [
    {
        rows: [
            { name: 'a'}
        ]
    },
    {
        rows: [
            { name: 'b'}
        ]
    },
    {
        rows: []
    }
];

var result = data.filter(f => f.rows && f.rows.length && f.rows.length > 0).map((currentValue) => {
  return currentValue.rows;
}).flat();

console.log(result);

The code above filters out empty rows first, maps the data, and flattens the final result.

Answer 2

Method 1:

To simplify your array, you can utilize the reduce method like so -

var data = [
    {
        rows: [
            { name: 'a'}
        ]
    },
    {
        rows: [
            { name: 'b'}
        ]
    },
    {
        rows: []
    }
]

var reducedSet = [];
data.reduce((accumulator, currentValue, currentIndex) => {
  var currentRows = currentValue.rows;
  var rowLength = currentRows && currentRows.length
  if (rowLength) {
    for (i = 0; i < rowLength; i++) {
            accumulator.push(currentRows[i]);
        }
    return accumulator;
  }
}, reducedSet);

console.log(reducedSet);

Method 2:

Alternatively, you can approach it in this way too -

var data = [
    {
        rows: [
            { name: 'a'}
        ]
    },
    {
        rows: [
            { name: 'b'}
        ]
    },
    {
        rows: []
    }
];

var result = data.filter(f => f.rows && f.rows.length && f.rows.length > 0).map((currentValue) => {
  return currentValue.rows;
}).flat();

console.log(result);

The code above filters out empty rows first, maps the data, and flattens the final result.

Answer 3

Answer №2

data = [
    {
        rows: [
            { name: 'a'},
        ]
    },
    {
        rows: [
            { name: 'b'},
        ]
    },
    {
        rows: []
    }
]

let transformedData = data.map(item => {
    return item.rows.map(innerItem => {
        return {
            name: innerItem.name
        }
    })
 })

transformedData = transformedData.flat()

console.log(transformedData)

You can give this a try, it seems to achieve the desired outcome based on my observations.

Answer 4

data = [
    {
        rows: [
            { name: 'a'},
        ]
    },
    {
        rows: [
            { name: 'b'},
        ]
    },
    {
        rows: []
    }
]

let transformedData = data.map(item => {
    return item.rows.map(innerItem => {
        return {
            name: innerItem.name
        }
    })
 })

transformedData = transformedData.flat()

console.log(transformedData)

You can give this a try, it seems to achieve the desired outcome based on my observations.

Answer 5

Answer №3

If you're looking for a solution, this code snippet may be of help. It is designed to handle scenarios where there are multiple occurrences of the name element within a single rows.

let data = [] // YOUR OBJECT IN THE QUESTION

    let data2: any = []
    data.forEach(el => {
    if(el.rows.length > 0) {
    data2 = [...data2, ...el.rows];
       
        }
})


console.log('data2', data2);

Answer 6

If you're looking for a solution, this code snippet may be of help. It is designed to handle scenarios where there are multiple occurrences of the name element within a single rows.

let data = [] // YOUR OBJECT IN THE QUESTION

    let data2: any = []
    data.forEach(el => {
    if(el.rows.length > 0) {
    data2 = [...data2, ...el.rows];
       
        }
})


console.log('data2', data2);

Answer 7

Answer №4

If you're looking to streamline it using the latest JavaScript techniques, this is how it's done.

const rearrangeData = (dataToTransform) => dataToTransform.reduce((transformedData, { rows }) => transformedData.concat(rows), []);

In essence, a fresh array is created and then for each item in the initial data set, the content of the rows property is extracted and added to the array.

Answer 8

If you're looking to streamline it using the latest JavaScript techniques, this is how it's done.

const rearrangeData = (dataToTransform) => dataToTransform.reduce((transformedData, { rows }) => transformedData.concat(rows), []);

In essence, a fresh array is created and then for each item in the initial data set, the content of the rows property is extracted and added to the array.

Answer 9

Answer №5

data.filter(item => {
  return item.rows !== [];
});

A filtering operation can be applied to the array.

Answer 10

data.filter(item => {
  return item.rows !== [];
});

A filtering operation can be applied to the array.

A guide on showcasing nested arrays data in an Angular application

Answer №1

Method 1:

Method 2:

Answer №2

Answer №3

Answer №4

Answer №5

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