I am looking to achieve the same functionality as the code below but without using any condition statements.
HelloFunction(x){
If(x<0){
Console.log("greater");
}Else{
Console.log("smaller");
}
};
HelloFunction(1);
HelloFunction(-1);
Utilizing an Object may seem unconventional, whereas employing an if...else statement or its succinct ternary form can better communicate the underlying logic, making it more transparent.
function Hello(x) {
const lt = {
true: "smaller",
false: "greater"
};
console.log(lt[x < 0]);
};
Hello(1);
Hello(-1);It might seem a bit unconventional to actually implement this, and it could be considered too specific for your particular scenario but...:
const greet = (x) => {
const check = x < 0;
console.log("positive".repeat(!check) + "negative".repeat(check));
};
greet(-1);
greet(1);Expanding on @Teemu's idea, a more adaptable approach could be:
const if_else = (condition_fn, if_function, else_function = (x) => x) =>
[else_function, if_function][+condition_fn()]();
const greet = (x) =>
if_else(
() => x < 0,
() => console.log('positive'),
() => console.log('negative')
);
greet(-1);
greet(1);@Teemu provided insight on accomplishing the task without any branching, which can prove advantageous in certain situations (see this discussion: Why is processing a sorted array faster than processing an unsorted array?).
function greeting(y) {
console.log(['bigger', 'smaller'][+(y < 0)]);
}
greeting(1);
greeting(-1);However, it must be noted that achieving desired functionality based on a specific condition inherently involves a form of conditional.
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