Adjust the current type in order to allow all properties to become optional

Looking at the structure of my base type:

type MyForm = {
  email: string;
  password: string;
}

I'm wondering if there's a possibility to change MyForm into this optional version:

type MyFormOptional = {
  email?: string | null;
  password?: string | null;
}

Can I achieve this transformation using only MyForm as a starting point?

Answer №1

Indeed, it is possible to define a mapped type that allows for each property to be optional by utilizing the ? mapping modifier, and also includes null as part of each property's type:

type PartialAndNullable<T> =
  { [K in keyof T]?: T[K] | null }

type MyFormOptional = PartialAndNullable<MyForm>
/* type MyFormOptional = {
    email?: string | null;
    password?: string | null;
} */

Link to code Playground

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