After filtering the array in JavaScript, perform an additional process as a second step

My task involves manipulating an array through two methods in sequence:

  1. Filter the array
  2. Then, sort it

The filter method I am using is as follows:

  filterArray(list){
    return list.filter(item => !this.myCondition(item));
  }

The sort method I am using is as follows:

sortArray(list) {
    return list.sort((a, b) => new Date(b.beginDate).getTime() - new Date(a.beginDate).getTime());
}

I want to ensure that the array is completely filtered before sorting it.

I have attempted the following:

myData = myData.filterArray(myData).sortArray(myData);

However, I am uncertain if this is the most efficient approach. (Note: I prefer to keep the sorting and filtering methods separate)

What are the best ways to achieve this?

Answer №1

Array.sort does not generate a fresh arranged array. It performs a in-place sorting operation, meaning it will alter the array. Therefore, it is illogical to retrieve and store a value from your sorting function. If you wish to prevent changes to the original array, you need to manually create a copy of it within your sorting function, then proceed with the sorting process before returning it. This approach ensures the functions remain pure without any unintended impacts;

sortArray(list) {
    let listClone = list.slice(0); // employing a rapid cloning method
    listClone.sort((a, b) =>
      new Date(b.beginDate).getTime() - new Date(a.beginDate).getTime()
    );
    return listClone 
}

Given that filter consistently generates a new array, your code functions correctly; however, if you utilize the sort function separately, it may result in unintended consequences.

Answer №2

  filteredData = myData
  .filter(item => !this.myCondition(item))
  .sort((a, b) => new Date(b.beginDate).getTime() - new Date(a.beginDate).getTime());

Each line has a unique function in the process.

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