Allowing for the acceptance of empty arguments when creating instances of a class in Typescript constructors

Here is my Typescript implementation of the User class:

class User {
  private name: string;
  private managerOf: User;

  constructor(name: string, managerOf: User) {
    this.name = name;
    this.managerOf = managerOf;
  }

  getName(): string {
    return this.name;
  }

  isManagerOf(user: User): boolean {
    return user.getName() == this.name;
  }

}

let jerry = new User("Jerry", null);
let jane = new User("Jane", jerry);

However, there is an error when passing null into Jerry's constructor:

Argument of type 'null' is not assignable to parameter of type 'User'

What can be done so that I am able to pass null for Jerry's managerOf value?

Here is a full reproducible example.

Answer №1

Is it essential to specify null in both the constructor and the field definition?

Absolutely, but this requirement stems from how the managerOf property is defined. It all hinges on the type of the property, and Typescript enforces that everything aligns accordingly.


You initially declared:

private managerOf: User;

This means only a User can be assigned to the managerOf property. As null is not a User, it is not permitted.

Moving on to the constructor:

class User {
  private name: string;
  private managerOf: User;

  constructor(name: string, managerOf: User) {
    this.name = name;
    this.managerOf = managerOf;
  }
}

new User('qwerty', null) // error

Here, you cannot pass in null because the constructor does not accept null. To resolve this issue:

class User {
  private name: string;
  private managerOf: User;

  constructor(name: string, managerOf: User | null) {
    this.name = name;
    this.managerOf = managerOf; // error
  }
}

new User('qwerty', null) // fine

Now, you are able to provide null as an argument for the constructor. However, null still does not match the allowed types for the managerOf property, resulting in an error upon assignment.

Therefore, allowing null in the managerOf property necessitates including it in the type definition.

The constructor parameter for managerOf is completely independent from the actual managerOf property of the instances of the class. Type safety is enforced by Typescript when assigning one to the other.


How could Typescript know that you want to avoid something like this?

class User {
  private name: string,
  private managerOf: User

  constructor(name: string, managerOf: User | null) {
    this.name = name
    this.managerOf = managerOf || defaultManager
  }
}

const jerry = new User("Jerry", null);
jerry.managerOf.name // returns the default name

In this scenario, you allow null in the constructor, assign a default value to the property if it is null. Cases like these justify the need to specify it in "both" places.


An alternative shorthand method exists for handling this situation:

class User {
  constructor(
    private name: string,
    private managerOf: User | null
  ) {}
}

new User('qwerty', null) // fine

With this syntax, a constructor argument can be directly assigned to an instance property, effectively declaring it only once.

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