Ambiguous typing: Element is implicitly considered to be of type 'any' due to the absence of an index signature for type 'Window'

I'm attempting to develop a Factory class in Typescript, however I've encountered the following issue:

src/ts/classes/Factory.ts(8,10): error TS7017: Element implicitly has an 'any' type because type 'Window' has no index signature.

I have searched for a solution to this error, but haven't found anything that directly addresses my specific situation.

Below is the code for my Factory class.

/**
 * @class Factory
 *
 * @description Returns object based on given class string
 */
class Factory {
    public getClass(className: string): any {
        return window[className];
    }
}

I prefer not to simply ignore implicit errors in the compiler.

Any advice or assistance on resolving this issue would be greatly appreciated! If there's a better approach to achieving the desired result, I am open to making adjustments as well.

Answer №1

If you want to index on the window without declaring it, you can simply cast it to type any:

return (window as any)[className];

Answer №2

The global window object is of type Window. Since the Window type does not have an index signature, TypeScript cannot determine the type of window[yourIndex].

To make your code work correctly, you can add the following interface to a non-module file:

interface Window {
    [key:string]: any; // Add index signature
}

It's important to note that this will allow access to any property on the window object, for example, window.getElmentById("foo") will no longer be flagged as an error even if it contains a typo.

Additionally, it's worth mentioning that relying on custom modifications to global variables can lead to issues in the future. Avoid using any when declaring types, as TypeScript is designed to provide specific type references. It is recommended to refrain from altering the global namespace and depending on the global window variable.

Answer №3

perhaps experiment with

retrieve the window object using className as a key of WindowType;

Answer №4

Here's another method to achieve this:

(<any>window).className

I encountered a similar problem while utilizing

window["webkitAudioContext"]
, but was able to solve it by using
(<any>window).webkitAudioContext

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