An error is raised when attempting to refactor [].concat.apply([], [x]) to [].concat(x)

When attempting to refactor

Array.prototype.concat.apply([], [x])
to [].concat(x), I encountered the following error message:

No overload matches this call.
  Overload 1 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type 'Moment | [Moment, Moment]' is not assignable to parameter of type 'ConcatArray<never>'.
      Type 'Moment' is missing the following properties from type 'ConcatArray<never>': length, join, slice
  Overload 2 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type 'Moment | [Moment, Moment]' is not assignable to parameter of type 'ConcatArray<never>'.
      Type 'Moment' is not assignable to type 'ConcatArray<never>'.ts(2769) 

I need help understanding what's causing this problem and how best to refactor the code.

Answer №1

One reason for this issue is that the [] is defined as never[]. When you utilize concat in the initial scenario with Array.prototype being any[], the concatenation occurs between any[] and (typeof x)[].

The argument is of type 'Moment | [Moment, Moment]'

If you aim to standardize it to Moment[], you can proceed as follows:

let y: Moment[];

y = ([] as any[]).concat(x);

// or an alternative method

y = "length" in x ? x : [x];

// or explore other possibilities during your refactoring process.

const [
  from = x,
  to = x
] = x as any;

You could also encapsulate this logic within a function:

function foo<T>(arg: T|T[]): T[] {
  return Array.isArray(arg) ? arg : [arg];
}

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