Searching for a more concise way to rewrite the following condition:
[ngClass]="{
'class1':
image.isAvailable && (image.property !== true && !null),
'class2':
image.isAvailable && (image.property === true && !null)
}"
Dealing with the scenario where image.property may be NULL and trying to manage it...feeling like I'm overlooking something obvious, any assistance would be greatly appreciated
To handle potential undefined properties, you can utilize the safe navigation operator ?. along with the ternary operator.
[ngClass]="(image?.isAvailable && image?.property) ? 'class1' : 'class2'"
The safe navigation operator ensures that a property is defined before attempting to access it.
Based on the original poster's requirement - do not apply any classes if image?.isAvailable is undefined.
You can expand the ternary operator to include an additional level to validate whether image?.isAvailable is defined before assigning the classes.
[ngClass]="image?.isAvailable ? (image?.property ? 'class1' : 'class2') : ''"
The use of an empty string '' indicates an empty class list if the image?.isAvailable property is undefined.
This code snippet demonstrates two ways to write the same logic:
[ngClass]="{
'class1':
image.isAvailable && !image.property),
'class2':
image.isAvailable && image.property)
}"
Alternatively, you can express it like this:
[class.class1]="image.isAvailable && !image.property"
[class.class2]="image.isAvailable && image.property"
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