Angular - creating a Toggle feature to swap out divs

I've been working on creating a toggle switch to swap out a section on a webpage with another div containing different content.

<!-- Toggle - Changes layout when clicked-->
<div class="content">
  <p class="leftBox" >option 1</p>
  <label class="switch" >
    <input type="checkbox" (click)="toggle()" >
    <span class="slider round" ></span>
  </label>
  <p class="rightBox" >option 2</p>
</div>


<div class="page1Text">


<!-- Page Content -->

</div>

<!-- Next Button -->
<div class="content">
  <button type="button" class="mat-raised-button buttontxt" (click)="nextpage1()">Next</button>
</div>
</div>


<!-- Page Content 2 -->
<ng-container *ngIf="show">
<div class ="page2" >
  

  <!-- Page Content -->
  <div class= "content text-center">
      
  <!-- Next Button - Link to either Growth or Mindset page, depending on toggle -->
  <div class="content">
    <button type="button" class="pam-button mat-raised-button buttontxt" (click)="nextpage2()">Next</button>
  </div>
</div>
</ng-container>

And here's my TypeScript:

 toggle(){
    this.show = !this.show;

    if(this.show)
      this.switch = "Hide";
    else
      this.switch = "Show";
  }

The second page content toggles effectively, but I'm struggling to figure out how to replace/hide the first page content using the same toggle switch and vice versa. Any suggestions would be appreciated!

Answer №1

To implement a toggle functionality, simply utilize templates based on specified conditions.

Here is a generic example showcasing a more streamlined syntax:


<ng-container *ngIf="displayContent; then showContentTpl; else hideContentTpl">
</ng-container>

<button (click)="displayContent = !displayContent">
  Toggle Content
</button>

<ng-template #showContentTpl>
  This section will display when the 'displayContent' variable equals true
</ng-template>

<ng-template #hideContentTpl>
  This section will display when the 'displayContent' variable equals false
</ng-template>

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