Angular - Implementing *ngIf based on URL parameters

Is it possible to display an element based on specific queryParams included in the URL?

For example:

ngOnInit() {
    this.route.queryParams.subscribe(params => {
        console.log(params);
    });
}

If I want to achieve something similar to this:

<div *ngIf="queryParams = 'query_name'"></div>

Answer №1

To utilize a specific query parameter in a condition, you must first assign it to a property and then reference that property within the *ngIf directive.

queryParameter;

ngOnInit() {
    this.route.queryParams.subscribe(params => {
        this.queryParam = params['yourParamName'];
    });
}

In your HTML markup:

<div *ngIf="queryParam == 'yourCondition'"></div>

Answer №2

When working in a .ts file, you can set up query parameters like this:

private queryParams:string ='';

ngOnInit() {
    this.route.queryParams.subscribe(params => {
        this.queryParams= params['parameterName'];

    });
}

To clarify, if the route is "/userId" the code should look like this:

this.queryParams= params['userId'];

When working in a .html file, you can use the following code snippet to check for specific query parameter values:

<div *ngIf="queryParams.toLowerCase() === 'queryName'.toLowerCase()"></div>

For example, if the intended string is "userName," the code would look like this:

 <div *ngIf="queryParams.toLowerCase() === 'userName'.toLowerCase()"></div>

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