Arrange the TypeScript array in alphabetical order first, followed by numbers, utilizing the Intl.Compare method

I need to sort an array of objects by their values.

Provided Input

let arr = ['4-5', 'null-4', '7-null', '1-2']

Desired Output

['null-4', '1-2', '4-5','7-null']

I attempted to utilize string.localCompare() in combination with value.split('-'), but it seemed to impact performance negatively. Then I experimented with Intl.Compare, however, the resulting order was

['null-4','7-null', '1-2', '4-5']
.

Is there a way to achieve the desired output using Intl.Compare?

Answer №1

Try running

arr = arr.map(s => s.replaceAll('null', '0'))
before sorting the array to see if it resolves the issue.

The reason you are getting your Output is because null - 4 == null and 7 - null == null

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