"Array.Find function encounters issues when unable to locate a specific string within the Array

Currently, I am utilizing an array.find function to search for the BreakdownPalletID when the itemScan value matches a SKU in the array. However, if there is no match found, my application throws a 'Cannot read property breakdownPalletID of undefined' error. Since the user inputs the itemScan value, I want to maintain this functionality while also informing the user that the specified string was not located. What approach should I take to manage this undefined error?

 let palletID = this.transferPalletBreakdownData.Sku.find(x => x.sku == this.itemScan)?.breakdownPalletID
      console.log(palletID);
javascripttypescript

Answer №1

When using the Array.prototype.find() method, if an item does not exist it will return null; otherwise, it will return the expected item. To avoid errors, simply add null checks.</p>

<pre><code> const itemFound = this.transferPalletBreakdownData.Sku.find(x => x.sku == this.itemScan)

let palletID = itemFound && itemFound.breakdownPalletID
console.log(palletID);

If you need to find more than one item based on matching criteria, use the filter method instead of find().

const matches = this.transferPalletBreakdownData.Sku.filter(x => x.sku == this.itemScan)

const items = matches.map(item => itemFound.breakdownPalletID)

console.log(items)

Answer №2

To retrieve the breakdownPalletID, you can employ the logical OR operator ||:

let palletID = (this.transferPalletBreakdownData.Sku.find(x => x.sku == this.itemScan) || {}).breakdownPalletID;
console.log(palletID);

Answer №3

Give this code a test run.

let selectedSKU = this.transferPalletBreakdownData.Sku.find(item => item.sku === this.itemScan);
if (selectedSKU) {
  console.log(selectedSKU.breakdownPalletID);
} else {
  console.log('SKU not found');
}

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