Attempting to invoke a promise within a function yields an error message stating that it lacks call signatures

Recently, I came across this interesting class:

export class ExponentialBackoffUtils {
    public static retry(promise: Promise<any>, maxRetries: number, onRetry?: Function) {
        function waitFor(milliseconds: number) {
            return new Promise((resolve) => setTimeout(resolve, milliseconds));
        }
        async function retryWithBackoff(retries: number) {
            try {
                if (retries > 0) {
                    const timeToWait = 2 ** retries * 1000;
                    await waitFor(timeToWait);
                }
                console.log('Retries: ', retries);
                if (retries < 3) {
                    throw new Error();
                }
                return await promise();
            } catch (e) {
                if (retries < maxRetries) {
                    if (onRetry) {
                        onRetry();
                    }
                    return retryWithBackoff(retries + 1);
                } else {
                    throw e;
                }
            }
        }

        return retryWithBackoff(0);
    }
}

I encountered an issue where Typescript was yelling at me for trying to call the promise that I passed in...But why? It was complaining that promise has no call signatures.

https://i.stack.imgur.com/iHQKK.png

Answer №1

You can't treat a Promise as a function, so avoid using the incorrect syntax of calling it with promise().

To correctly handle a promise, just use await promise without the parentheses.

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