Bizarre Behavior of String Comparison in Typescript When Using String.toLowerCase

As someone who is naturally curious (and has no background in JS), I have decided to take the plunge into Typescript. However, I seem to have hit a roadblock. I am trying to compare two strings but want to make it easier by first converting them to lowercase. Below is the code snippet that I am using:

let bool: boolean = false;
let i = 0;
this.comparisons[++i] = " init bool " + " => " + bool;

bool = false;
if ("a" == "a") { bool = true };
this.comparisons[++i] = ' "a" == "a" ' + " => " + bool;

bool = false;
if ("a" == "b") { bool = true };
this.comparisons[++i] = ' "a" == "b" ' + " => " + bool;

bool = false;
if ("a" == "A") { bool = true };
this.comparisons[++i] = ' "a" == "A" ' + " => " + bool;

bool = false;
if ("a".toLowerCase == "A".toLowerCase) { bool = true };
this.comparisons[++i] = ' "a".toLowerCase == "A".toLowerCase ' + " => " + bool;

bool = false;
if ("a".toLowerCase == "B".toLowerCase) { bool = true };
this.comparisons[++i] = ' "a".toLowerCase == "B".toLowerCase ' + " => " + bool;

Upon execution, the output is as follows:

init bool => false

"a" == "a" => true

"a" == "b" => false

"a" == "A" => false

"a".toLowerCase == "A".toLowerCase => true

"a".toLowerCase == "B".toLowerCase => true

I am puzzled as to why the last comparison evaluates to true.

In my understanding, "a" == "b" should evaluate to false just like the third statement. What could be causing this unexpected behavior?

Answer №1

Remember to always include parentheses () when calling a method, even if there are no arguments:

bool = false;
if ("a".toLowerCase() == "B".toLowerCase()) { bool = true };

Alternatively, you can simplify it to:

bool = ("a".toLowerCase() == "B".toLowerCase());

If you leave out the parentheses, "a".toLowerCase will only reference the method String.toLowerCase itself. In this case, the comparison returns true because it's comparing the two methods and identifying them as the same.

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