Break down a data structure into a type that includes multiple options

Is it possible for Typescript to support type or interface "destructuring" (if that's the right term)?
I am attempting to achieve something similar to the code snippet below:

type SomeRandomType = {
    propertyOne: string;
    propertyTwo: number;
    ...
};

type SomeRandomORType = "propertyOne" | "propertyTwo" | ...;

Can we create SomeRandomORType without manually typing properties from SomeRandomType? Something like this:

type SomeRandomORType = Destruct<SomeRandomType>;

Answer №1

If you want to access the names of each property in an interface or object with a type that could be a string or number, you can use the keyof operator. This seems like it could be what you are searching for.

interface myInterface {

    property1: string;
    property2: string;
    property3: number;
}

type keysOfMyInterface = keyof myInterface;

// This assignment is valid as "property1" exists in the interface.
const variable1: keysOfMyInterface = "property1";

// This assignment is invalid as "property4" does not exist in the interface.
const variable2: keysOfMyInterface = "property4";

You can experiment with this concept here

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