Breaking down an array into function arguments in TypeScript/JavaScript

I am working with an array of object instances that have different types.

var instances: any = [];
instances["Object1"] = new TypeA();
instances["ObjectB"] = new TypeB();

Each type has its own methods with unique names and varying numbers of arguments. I am looking for a way to call these methods using a single function, passing data from the client to identify the method to call and provide necessary argument values.

function CallMethod(data){
  let args = data.args; // it's an array
  instances[data.objectId][data.methodId](??????); 
}

Is there a way to automatically break down the args array to pass its values as separate function arguments?

For example:

instances[data.objectId][data.methodId](args[0], args[1], ... args[n]); 

Answer №1

Utilize the power of the Spread Syntax

function ExecuteMethod(data){
  let arguments = data.arguments;// this is an array
  objects[data.objectId][data.methodId](...arguments); 
}

Answer №2

To utilize spread syntax, you can destructure an array for function parameters by using .... This concept is commonly referred to as spread. For further information, you can explore the topic here.

instances[data.objectId][data.methodId](...args); 

Therefore, your function should appear as follows:

function CallMethod(data){
    let args = data.args; // representing an array
    instances[data.objectId][data.methodId](...args); 
}

Answer №3

The spread syntax operator is effective in this scenario

function ExecuteFunction(data){
  let arguments = data.arguments;
  objects[data.objectIdentifier][data.methodIdentifier](...arguments); 
}

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