Can a strict type be created from a partial type?

By utilizing TypeScript 2.1, we have the ability to generate a partial type from a strict type as demonstrated below:

type Partial<T> = {
    [P in keyof T]?: T[P];
};
type Person = { name: string, age: number } 
type PersonPartial = Partial<Person>; // === { name?: string, age?: number }

However, the question arises: is it feasible to derive a strict type from a partial type?

type Strict<T> = { ??? };

type Person = { name: string; age?: number; }
type PersonStrict = Strict<Person>; // === { name: string, age: number }

Desired Outcome

I am in need of the following two types, without the need for redundant declarations.

type Person = { name: string, age?: number, /* and other props */ }
type PersonStrict = { name: string, age: number, /* and other props */ }

While a verbose solution exists, I am curious if there is a more efficient approach available.

type RequiredProps = { name: string, /* and other required props */ };
type OptionalProps = { age: number, /* and other optional props */ };
type Person = RequiredProps & Partial<OptionalProps>;
type PersonStrict = RequiredProps & OptionalProps;

Answer №1

Implement the Required type for TypeScript.

type User = { username: string; email?: string; }
type RequiredUser = Required<User>; // === { username: string, email: string }

Answer №2

I finally cracked the code.

interface Individual = { label: string, id?: number };
interface Precise<T> = { [K in (keyof T)]: T[K] };
interface IndividualPrecise = Precise<Individual>;

Make sure to include parentheses with keyof T.

Leaving out these parentheses will keep id as optional.

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