Can a universal type be designed for application across various types?

I've got this function:

function stackPlayer(stack){

}

The stack parameter can have one of the following forms only:

  1. a function that takes req, res, and next as arguments.
  2. a function that takes req, res, and next as arguments, and returns a function that also takes req, res, and next.
  3. a function that takes req, res, and next as arguments, and returns an array of functions that also take req, res, and next.
  4. an array of functions that take req, res, and next as arguments.

For example:

// Examples of valid arguments:
(req, res, next) => {} // or
(req, res, next) => (req, res, next) => {} // or
(req,res,sNext) => [(req,res,sNext)=>{}] // or
[(req,res,sNext)=>{}]

To simplify the type of the parameter in the function, I came up with the following solution which makes it easier to read and understand:

type Smiddleware = <T = void>(req: Request, res: Response, next: NextFunction) => T
type Stack = Smiddleware<void> | Smiddleware<Smiddleware> | Smiddleware<Smiddleware[]> | Smiddleware[]

This approach is more concise and clear, but unfortunately not valid.

Answer №1

To optimize your code, consider moving the generic parameter to the Smiddleware type instead of keeping it inside the function.

Here's an example:

type Smiddleware<T> = (req: Request, res: Response, next: NextFunction) => T
type Stack = Smiddleware<{}> | Smiddleware<Smiddleware<{}>> | Smiddleware<Smiddleware<void>[]> | Smiddleware<void>[]

This way, you can easily swap out the generic types with other alternatives based on the function's return value.

For instance:

type Stack = Smiddleware<{}> | Smiddleware<number> | Smiddleware<Smiddleware<string>>

If you prefer using Smiddleware without specifying the type each time, you can set a default value for the generic parameter:

type Smiddleware<T = void> = ... // same as previous implementation 

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