Can an object type be partially defined?

Here is a similar scenario:

function(param1, { knownParam1, ...opts })

To better describe param1 and knownParam1, perhaps something like this could work:

type Param2 = {
   knownParam1: string,
   ...otherParams: any
}
type Parameters = {
   param1: string
   param2: Param2
}

Do you think TypeScript supports this kind of concept? It seems like it might not fully support destructuring yet.

Answer №1

Achieving your desired outcome is possible using the following code snippet:

type Parameters = { 
    specifiedParam: string;
    [identifier: string]: unknown;
}

function customizedFunction(param1: string, param2: Parameters) {
    const {
         specifiedParam,
         ...options
    } = param2;

    // Additional functionality here...
}

The parameters in the second argument are defined as an object containing known properties combined with any other properties of unknown data type.

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