Can callback argument types be contingent on certain conditions? For example, could argument 0 be null if argument 1 is a string?

I am attempting to implement conditional type logic for the parameter types of a callback function.

In this scenario, the first argument represents the value while the second argument could be an error message.

type CallbackWithoutError = (value: string, error: undefined) => void
type CallbackWithError = (value: undefined, error: string) => void

declare const foo: (cb: CallbackWithError | CallbackWithoutError) => void

// Assuming CallbackWithError initially
foo((value, error) => {
   if (error) {
      // handle error
      return
   }
   // Switching to CallbackWithoutError after checking for error
   console.log(value)
})

Is it feasible for TypeScript to assume that the callback function has the parameters related to errors defined first?

The code snippet shows how the presence of the 'error' parameter determines which type of callback (with or without error) will be used in subsequent operations.

Answer №1

It appears that utilizing discriminating tuples could be helpful in this case:

// Define the parameters to only accept one of two tuple types:
type Callback = (...p: [string, undefined] | [undefined, string]) => void

declare const foo: (cb: Callback) => void

foo((...p) => {
    if (p[1] !== undefined) {
        // handle
        return
    } else {
        console.log(p[0]) // TypeScript recognizes it as a string at this point.
    }
})

For more details, check out this Playground Link.

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