Can we destruct and type the properties of a function parameter object that are already known?

Typescript playground

Scenario: Creating a function that takes a single object with predefined properties, where we need to destructure and assign simultaneously.

The following method works as intended:

type OBJECT_PARAM = {
  pathname: string,
  routePath: string
}

export const getSlugMatch = (props: OBJECT_PARAM)
: string => {
    const { pathname, routePath } = props;
    return "SOME_SLUG";
};

This approach, however, does not achieve the desired outcome:

export const getSlugMatch_V2 = ({pathname: string, routePath: string}): string => {
    return "SOME_SLUG";
};

https://i.sstatic.net/SDIYe.png

Is there an alternative solution to this issue? How do other developers typically address this scenario? Is it necessary to explicitly define the OBJECT_PARAM type?

It seems that the problem arises from conflicting with JavaScript's approach to renaming destructured properties. What would be the most effective workaround in this situation?

Answer №1

To ensure clarity and avoid confusion with property renaming, it is recommended to keep destructuring separate from the type declaration. The most effective approach is to define the type directly within the function signature:

export const findMatch_V2 = ({path, route}: {path: string, route: string}): string => {
    return "MATCH_FOUND";
};

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