Can we incorporate 'this' in the super() constructor?

While reviewing someone else's code, I came across the following snippet:

class foo extends bar {
    constructor() {
        super(param1, param2, new certainObject(this, otherParams));
    }
}

The issue with this code is that it generates an error stating that 

'super' must be called before accessing 'this' in the constructor of a derived class
.

I am wondering if there is a way to incorporate the use of this within the call to super(), or if I will need to completely modify the code structure?

typescriptconstructor

Answer №1

It seems there is no straightforward way to utilize 'this' before the super call without resorting to hacky solutions (as indicated by the error message).

The TypeScript manual provides some insight on this topic. Additionally, a related but distinct GitHub issue has been opened to explore possibilities for allowing certain non-'this' code to be executed prior to calling 'super'.

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