I need help with creating a Regex in JavaScript
const pattern = /S(\d+)E(\d+)/; // identifying characters between "S" and "D"
const result = 'SE01E09'.match(pattern);
How should I declare the result variable?
I have attempted various approaches like the one below but haven't been successful
const result: Array<string | number> = 'SE01E09'.match(pattern);
To discover the inferred type, simply hover over a value in your IDE and view the tooltip. In this case, it would be: RegExpMatchArray | null.
If you want to delve deeper, try going to the definition by Alt + clicking (this shortcut may vary depending on your IDE). You might need to manually input the text for the link to be clickable, like so:
type R = RegExpMatchArray;
// ---------------- now you can Alt + click this
This example showcases two definitions:
// from lib.es5.d.ts
interface RegExpMatchArray extends Array<string> {
/**
* The index of the search at which the result was found.
*/
index?: number;
/**
* A copy of the search string.
*/
input?: string;
/**
* The first match. This will always be present because `null` will be returned if there are no matches.
*/
0: string;
}
// from lib.es2018.regexp.d.ts
interface RegExpMatchArray {
groups?: {
[key: string]: string
}
}
With interface merging, RegExpMatchArray is expected to exhibit both behaviors.
You should now have the tools to explore further.
This expression will result in a RegExpMatchArray | null.
let finalResult: RegExpMatchArray | null = 'Chapter7'.match(expression);
If you need more information, you can visit this link
If you had taken into account the potential null return value for cases where there is no match, your code would have functioned correctly with the array type:
const result: Array<string | number> | null = 'SE01E09'.match(pattern);
It is unnecessary to explicitly specify the inferred type RegExpMatchArray. Since you will only receive an array of strings in case of a match, this simplified version would suffice:
const result: string[] | null = 'SE01E09'.match(/\d+/g);
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