Cannot execute example of type alias in Typescript

While delving into the Typescript documentation, I came across the concept of type alias and found an interesting example here.

type DescribableFunction = {
  description: string;
  (someArg: number): boolean;
};
function doSomething(fn: DescribableFunction) {
  console.log(fn.description + " returned " + fn(6));
}

However, simply running this example doesn't output anything because the doSomething function is not invoked anywhere. To make the function property in the DescribableFunction type more descriptive, I attempted to modify it like this, although it proved ineffective.

type DescribableFunction = {
  description: string;
  (someArg: number): boolean;
};
function doSomething(fn: DescribableFunction) {
  console.log(fn.description + " returned " + fn(6));
}

const new_fn: DescribableFunction = {
  description: "test",
  () { // what should I include here?
    return true;
  },
};

doSomething(new_fn);

Answer №1

To create an object that can be assigned to this type, you can utilize the Object.assign() method.

const new_fn: DescribableFunction = Object.assign(
  (someArg: number) => { return true }, 
  { description: "test" }
)

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