Asking for help with converting a "boolean bit array" to a number:
const array: boolean[] = [false, true, false, true]; // 0101
Any ideas on how to achieve the number 5 from this? Appreciate any suggestions. Thanks!
Asking for help with converting a "boolean bit array" to a number:
const array: boolean[] = [false, true, false, true]; // 0101
Any ideas on how to achieve the number 5 from this? Appreciate any suggestions. Thanks!
I am not familiar with TS, but in pure JS, you can achieve the following:
a = [false, true, false, true]
b = a.reduce((res, x) => res << 1 | x)
alert(b)If you want to go from number to array:
b = 5
a = b ? [] : [false]
while(b) {
a.push((b &1) === 1)
b >>= 1
}
alert(a)Alternatively,
b = 5
a = b.toString(2).split('').map(x => x === '1');
alert(a)This code snippet is compatible with TypeScript.
async convertBoolToInt(boolArray:boolean[]){
let debugMode = true;
if(debugMode){
console.log('Debug : "convertBoolToInt" Started');
console.log('boolArray = ' + boolArray);
}
let bitArray:number[] = [];
boolArray.forEach((element) => {
bitArray.push(+element); //convert boolean to bit
});
if(debugMode){
console.log('bitArray = ' + bitArray);
}
let result: any = bitArray.reduce((accumulator: number, currentValue: number) => accumulator << 1 | currentValue); //perform bitwise conversion to integer
if(debugMode){
console.log('result = ' + result);
console.log('Debug : "convertBoolToInt" Finished');
}
return result
};
To achieve this task, I recommend using a simple approach of converting numbers to binary and using string split/join functions.
const convertToBinary = (num: number): Array<boolean> => (num).toString(2).split('').map(bit => bit === '1')
const convertToNumber = (arr: Array<boolean>): number =>
parseInt(arr.map(bit => bit ? '1' : '0').join(''), 2)
By utilizing the convertToNumber function, you can test it by checking:
console.log(convertToNumber([false, true, false, true])) // 5
Explores the concept of representing an array of boolean values as a number and vice versa, even though it does not directly answer the initial question.
const boolsToNum = (bools: boolean[]) => {
return bools.reduceRight((res, bool) => res << 1 | +bool, 1)
}
const numToBools = (num: number) => {
const bools = []
while (num > 1) {
bools.push((num & 1) === 1)
num >>= 1
}
return bools
}
The use of reduceRight() instead of reduce() eliminates the need for reversing the array when converting back to bools. By setting the initial value to 1 instead of 0, the array size is preserved and starts with false values. This approach emulates having an additional true value at the beginning of the array, saving the need to check the array length later on. The extra bit is disregarded during conversion back using while (num > 1).
const array:Array<boolean> = [false, true, false, true]; // 0101
console.log(array, 'original')
const num = boolsToNum(array)
console.log(num, 'compressed')
console.log(numToBools(num), 'uncompressed')
// (4) [false, true, false, true] original
// 26 compressed
// (4) [false, true, false, true] uncompressed
Implement a simple approach
function binaryArrayToNumber(arr) {
let result = 0;
for (let index = 0; index < arr.length; index++) {
if (arr[arr.length - index - 1]) {
result += 2 ** index;
}
}
return result;
}
console.log(binaryArrayToNumber([true, false, true])); // 5
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