What is a more graceful method for checking if a variable is truthy but also passes when it's equal to 0? The current verification
if(var !== undefined && var !== null)undefined or NaN. Furthermore, I am utilizing TypeScript and have declared it as an optional number.
To achieve the request made in your initial statement, you can use the following code:
if (!x && x !== 0)
This condition translates to "if x is falsy and not equal to 0."
It's worth noting that the == and != operators treat null and undefined as equivalent values, so the expression
if (x != null)
would evaluate to true for both null and undefined. Remember, this uses != and not !==.
function Validate(inputValue) {
if (!inputValue && inputValue!==0){
return "falsy";
}
else if (inputValue === 0){
return "zero";
}
}
console.log(Validate(0));
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