Checking that an object's keys are all present in an array in TypeScript should be a top priority

I am working with a const object that is used to simulate enums. My goal is to extract the keys from this object and store them in an array. I want TypeScript to generate an error if any of these keys are missing from the array.

// Enum definition.
export const Status = {
    'ACTIVE': 'Active',
    'DELETED': 'Deleted'
} as const;

// Enum keys and values.
export type StatusKeys = keyof typeof Status;
export type StatusValues = typeof Status[StatusKeys];

// I want TypeScript to detect any missing keys like 'DELETED' and trigger an error.
// Ideally, this process should be dynamic without the need for manual maintenance.
export const ArrayStatus: StatusKeys[] = ['ACTIVE'];

The purpose of this setup is to ensure that I receive errors whenever I add or remove entries from the const object, prompting me to update my code accordingly.

Answer №1

If you're looking for a union type that has been converted to an array with typechecking.

Check out this resource -> , it might be just what you need.

For example:

// Defining my Enum.
export const Status = {
    'ACTIVE': 'Active',
    'DELETED': 'Deleted'
} as const;

// Enum keys and values.
export type StatusKeys = keyof typeof Status;
export type StatusValues = typeof Status[StatusKeys];

// Ensuring TypeScript detects the absence of 'DELETED' and throws an error.
// Ideally done dynamically without the need for an additional variable.

type TupleUnion<U extends string, R extends any[] = []> = {
    [S in U]: Exclude<U, S> extends never ? [...R, S] : TupleUnion<Exclude<U, S>, [...R, S]>;
}[U];

export const ArrayStatus: TupleUnion<StatusKeys> = ['ACTIVE', 'DELETED'];

export const ArrayStatusNoDelete: TupleUnion<Exclude<StatusKeys, 'DELETED'>> = ['ACTIVE']

TS Playground

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