Combining nested Observables within an outer array without using inner subscribe (RxJS)

Looking at the TypeScript functions below, which are used for async HTTP-Calls:

public retrieveAllMembersIdsFromGroup(groupId: string): Observable<string[]>
public retrieveMember(memberId: string): Observable<Member>

How can these be combined into a single function to obtain all members (Observable)?

public combineAllMembersFromGroup(groupId: string): Observable<Member[]>

For instance, we aim to achieve something similar to this:

public combineAllMembersFromGroup(groupId: string): Observable<Member[]> {
return this.retrieveAllMembersIdsFromGroup(groupId).pipe(
      map((membersIds: string[]) => {
        //perform necessary actions here to call this.retrieveMember(memberId)
        return //Observable<Member[]>;
      })
    );
}

If possible, it is preferred not to subscribe to the retrieveAllMembersIdsFromGroup method in order to avoid manual processing of the ids. What would be the optimal solution?

Answer №1

It's unclear what kind of magic you're seeking, but perhaps this solution could meet your needs?

public getAllMembersFromGroup(groupId: string): Observable<Member[]> {
    return this.getAllMemberIdsFromGroup(groupId).pipe(
      concatMap((memberId: string) => {
        return this.getMember(memberId);
      })
    );
}

I also made some changes to names for better clarity and grammar.

Answer №2

Below is the solution that I found effective:

function getMembersOfGroup(groupID: string): Observable<Member[]> {
    return from(getAllMemberIDsOfGroup(groupID)).pipe(
      mergeMap((memberIds: string[]) => {
        const members$: Observable<Member>[] = [];
        memberIds.forEach((id: string) => {
          members$.push(retrieveMemberDetails(id));
        });
        return combineLatest(members$);
      })
    );
}

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