Conceal components using routing in Angular2 release candidate 1

I have a request regarding certain elements that are to be displayed on all pages except the login page. I am considering using either ngIf or the hidden property of the elements to hide them when the user is on the login page.

Here is what I have attempted:

<div [hidden]="router.isRouteActive(router.generate('/login'))">

This method was suggested in response to a similar question found here: In Angular 2 how do you determine the active route?

In addition, I also tried:

<div *ngIf="!router.isRouteActive(router.generate('/login'))">

Unfortunately, neither attempt has been successful so far.

For further context, below is the component corresponding to this HTML code.

import { Component, OnInit } from 'node_modules/@angular/core';
import { HTTP_PROVIDERS, XHRBackend } from 'node_modules/@angular/http';
import { Routes, Router, ROUTER_DIRECTIVES } from 'node_modules/@angular/router';

import { LoginService } from './login/login.service';
import { LoginComponent } from './login/login.component';
import { UserComponent } from './user/user.component';

@Component({
    selector: 'portal',
    templateUrl: 'portal/portal.component.html',
    directives: [ROUTER_DIRECTIVES, LoginComponent, UserComponent ],
    providers: [
        HTTP_PROVIDERS,
        LoginService
    ]
})

@Routes([
    { path: '/login', component: LoginComponent},
    { path: '/user/:username', component: UserComponent}
])

export class PortalComponent implements OnInit{
    private router: Router
    constructor() {}

    ngOnInit() {
        this.router.navigate(['/login']); 
    } 
}

The information available on isRouteActive and generate methods is limited. Can someone provide guidance on a more effective approach to achieve this functionality?

Answer №1

To easily determine if the user is on the login page, just check the router.url in your template:

my.component.ts

...
constructor(public router: Router){}
...

my.component.html

<div *ngIf="router.url != '/login'">
    <h2>You are not currently in the login page!</h2>
</div>

Answer №2

When working with Angular2 RC5 router, I utilized the following code:

import {Router} from '@angular/router';

public endpoint = '' ;

constructor(private  _router : Router) 
{      
  this.endpoint = _router.url;
}

For HTML implementation:

<div *ngIf = "endpoint == '/home' ">
</div>

I hope you find this information helpful!

Answer №3

After some searching, I finally found the solution I was looking for in a comment on this page: In Angular 2 how do you determine the active route?

<div *ngIf="!router.urlTree.contains(router.createUrlTree(['/login']))">

Answer №4

To toggle the visibility of elements based on the URL's specific component, follow these steps:

Update your component.ts file with the code snippet below:

import { RouterModule, Router, NavigationEnd } from '@angular/router';

hideElement = false;

constructor(private router: Router) {
  this.router.events.subscribe((event) => {
    if (event instanceof NavigationEnd) {
      if (event.url === '/login') {
        this.hideElement = true;
      } else {
        this.hideElement = false;
      }
    }
  });
}

Then, utilize the hideElement property in your component.html like so:

<div [hidden]="hideElement">

Answer №5

When working on my code, I encountered a similar situation that required me to programmatically exclude certain routes from displaying an element.

To achieve this, I utilized the Location object provided by @angular/common.

public isElementHidden() {
  let excludedRoutes = ["/login"],
      currentRoute = this.location.path();

  return (excludedRoutes.indexOf(currentRoute) > -1);
}

Within my template, I leveraged the hidden attribute and bound it to the output of the function.

<div id="elementToHide" [hidden]="isElementHidden()"></div>

Answer №6

None of the proposed solutions yielded the desired outcome. If your route contains parameters, you can leverage ES6 includes:

<div *ngIf="!_router.url.includes('login')">Display this only if not on login page</div>

Answer №7

Here's a clever hack that can be used in certain scenarios. By utilizing the RouterLinkActive directive, we are able to apply it not only to anchors but also to their parent elements. This allows us to achieve the following:

<div routerLinkActive="hidden">
    <a routerLink="/login">Login</a>
</div>

The class hidden is taken from Bootstrap's standard styling:

.hidden {
    display: none!important;
}

How does it function? When you are in the login section, the hidden class is added, making the div invisible. As soon as you navigate to a different route, the hidden class is removed and the div becomes visible again.

One downside to note is that there must be a link with routerLink placed inside the div.

Answer №8

Example of using RxJS with Observables:

@Component({
  ...
})
export class AppComponent{
    hideElement$: Observable<boolean> = this.router.events
        .pipe(
            filter((event) => event instanceof NavigationEnd),
            map((data: any) => data.url === '/login')
        );
}
<ng-container *ngIf="!(hideElement$ | async)">
  <p>Only display this text if not on the Login page!</p>
</ng-container>

Answer №9

Referencing @Michelangelo's input:

Incorporating into Your Component:

import { Routes, Router } from 'node_modules/@angular/router';

export class YourComponent implements OnInit{
     constructor(public router: Router ) {
    }
}

Implementing in HTML:

<ng-container *ngIf="!router.url.includes('admin')">
    <p>Content to be hidden when the URL path is as specified above</p>
</ng-container>

Answer №10

If you're working with newer versions of angular 2, there is a more efficient way to handle transcluded content in specific route components. Rather than managing a list of routes and using ngIf conditions, you can selectively add the content where it's needed.

Simply add an ngcontent element in your component template and use select to assign it a name:

<ng-content select="[content-name]"></ng-content>  

Then, when using that component, you can easily transclude the content like this:

<component>
<div content-name> transcluded content</div>
</component>

Alternatively, you can use the component without referencing the transcluded content at all:

<component>
</component>

Answer №11

Instead of using router.generate('/login'), have you considered trying router.generate(['/login'])?

It can be a bit tricky to get the syntax just right.

I hope this suggestion is helpful for you!

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