Conditional types in Typescript that rely on their presence or absence in a dictionary

I am currently attempting to write a function with a complex type signature. It requires two dictionaries, args and funcs. The funcs dictionary maps keys to functions that transform type A to B, while the args dictionary maps a superset of those keys to either A if the key is in funcs, or B otherwise. Essentially, if a function exists for a certain key, use it to map the value from the same key in the other dictionary; if not, simply use the value itself.

Here is what I have so far, but it doesn't seem to be functioning as expected:

function foo<Properties>(
  args: { [P in keyof typeof funcs]: Parameters<typeof funcs[P]>[0] } & {
    [P in Exclude<keyof Properties, keyof typeof funcs>]?: Properties[P];
  },
  funcs: { [P in keyof Properties]?: (attributes: any) => Properties[P] }
) {}

interface Bar {
  x: number;
  y: string;
}

foo<Bar>(
  {
    x: "a",
    y: 1,
  },
  {
    y: (a: string) => "a",
  }
);

In this scenario, I would anticipate encountering two errors: one stating that x should correspond to a number in the first dictionary, and another indicating that y should be a string in the first dictionary. It appears that I may have misjudged TypeScript's capabilities - is achieving this intended behavior even possible?

Answer №1

Great puzzle!

I believe this solution will meet your desired objective:

type Function<Input, Output> = (argument: Input) => Output
type Functions<Type> = { [Key in keyof Partial<Type>]: Function<Key, Type[Key]> }

declare function transformer<Properties>(
  arguments: Properties,
  functions: Functions<Properties>
): void;

interface Foo {
  a: number;
  b: string;
}

transformer<Foo>(
  {
    a: 5,
    b: "bar",
  },
  {
    b: (value: string) => "10",
  }
);

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