Create a function that accepts a class as a parameter and outputs an object of that class

I am working on an instantiator function that generates an instance of a provided class:

declare type ClassType = { new (): any }; // known as "ParameterlessConstructor"

function createInstance(constructor: ClassType): any {
    return new constructor();
}

Is there a way for me to modify the function so that it produces an instance of the specified constructor, rather than just returning any? I want to ensure type safety for users of this function.

Answer №1

It turned out to be surprisingly simple; all I had to do was work around the limitations imposed by my own code.


The secret lies in defining the constructor parameter as a type that can create a new instance of a generic type. This generic type, T, must match the generic type returned by the getInstance function:

function getInstance<T>(constructor: { new (): T }): T {
    return new constructor();
}

By following this approach, the expected outcomes can be achieved:

class Foo {
    public fooProp: string;
}

class Bar {
    public barProp: string;
}

var foo: Foo = getInstance(Foo); // No issues
var bar: Foo = getInstance(Bar); // Error: Type 'Bar' is not compatible with type 'Foo'

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