Create a new data structure in TypeScript that stores multiple values in a

Question

Create a new data structure in TypeScript that stores multiple values in a

For my TypeScript project, I came across a situation where I needed to utilize Promise.all(...) to handle an array of multiple items:

Promise.all(
  firstRequest,
  secondRequest,
  ...,
  nthRequest
)
.then((array : [FirstType, SecondType, ..., NthType]) => {
  // process the responses here
});

The type definition

[FirstType, SecondType, ..., NthType]

was too long to include in the same block, so I attempted to define it separately and refer to it at that point.

I tried the following approach:

export interface ResponseParams {
  [0]: FirstType;
  [1]: SecondType;
  ...
  [n]: NthType;
}

And then used it like this:

.then((array : ResponseParams) => {
  // process the responses here
});

However, I encountered the error message:

Type 'ResponseParams' is not an array type.

Is there a way to externalize the type declaration to improve the cleanliness of my code?

Appreciate any insights. Thank you!

typescript

Answer 1

Answer №1

To create a specific type, you can utilize a type alias:

type CustomType = [FirstType, SecondType, ..., NthType]

Keep in mind that the type of array can be automatically inferred without explicit annotation (for up to 10 promises):

declare let firstRequest: Promise<{a: number}>
declare let secondRequest: Promise<{b: number}>
declare let nthRequest: Promise<{c: number}>
Promise.all([
    firstRequest,
    secondRequest,
    nthRequest
])
.then((array) => { // array is determined as [{a: number;}, {b: number;}, {c: number;}]      
// perform actions with response
});

Answer 2

To create a specific type, you can utilize a type alias:

type CustomType = [FirstType, SecondType, ..., NthType]

Keep in mind that the type of array can be automatically inferred without explicit annotation (for up to 10 promises):

declare let firstRequest: Promise<{a: number}>
declare let secondRequest: Promise<{b: number}>
declare let nthRequest: Promise<{c: number}>
Promise.all([
    firstRequest,
    secondRequest,
    nthRequest
])
.then((array) => { // array is determined as [{a: number;}, {b: number;}, {c: number;}]      
// perform actions with response
});

Answer 3

Answer №2

When using Promise.all, you have the ability to define a generic T, allowing for precise control over the return type. This enables you to specify the expected tuple for each promise while still preserving type integrity.

If I were to implement this using async / await syntax:

interface Foo {
    gnarf: string;
}

interface Bar {
    poit: string;
}

const createFoo = async (): Promise<Foo> => {
    return {
        gnarf: "random",
    };
};

const createBar = async (): Promise<Bar> => {
    return {
        poit: "hurz",
    };
};

const doStuff = async () => {
    const [foo, bar] = await Promise.all<Foo, Bar>([createFoo(), createBar()]);

    return `${foo.gnarf} and ${bar.poit}`;
};

doStuff().then(console.log).catch(console.error);

Answer 4

When using Promise.all, you have the ability to define a generic T, allowing for precise control over the return type. This enables you to specify the expected tuple for each promise while still preserving type integrity.

If I were to implement this using async / await syntax:

interface Foo {
    gnarf: string;
}

interface Bar {
    poit: string;
}

const createFoo = async (): Promise<Foo> => {
    return {
        gnarf: "random",
    };
};

const createBar = async (): Promise<Bar> => {
    return {
        poit: "hurz",
    };
};

const doStuff = async () => {
    const [foo, bar] = await Promise.all<Foo, Bar>([createFoo(), createBar()]);

    return `${foo.gnarf} and ${bar.poit}`;
};

doStuff().then(console.log).catch(console.error);

Create a new data structure in TypeScript that stores multiple values in a

Answer №1

Answer №2

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