Create a new interface to encapsulate the intersect type

Everywhere I look, I seem to be writing the following:

product: Product & { id: string; };

Is there a way for me to simplify this to:

product: WithId<Product>;

I attempted to create an interface like the one below, but encountered issues with extending from generics:

export interface WithId<T> extends T {
    id: string;
}

Answer №1

You have the option to simplify the concept by using abstraction of & {id: string}

export type WithId<T> = T & { id: string }

type Example = WithId<{ a: number }> // {a: number, id: string}
const example: Example = {a: 1, id: 'id'}

PS. { [K in keyof T]: T[keyof T] } is essentially the same as T itself, making it redundant.

Answer №2

One way to ensure a specific type in TypeScript is by using a type intersection

export type WithId<T> = { [K in keyof T]: T[keyof T] } & { id: string }


interface product { myNew: string }
let et: WithId<product> = { myNew: "s", id: "s" } // This is valid
let et: WithId<product> = { test: "s", id: "s" } // This will result in an error

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