I am seeking to create a callable function foo() (without using the new operator) that will also include a property foo.bar(). The JavaScript implementation would be as follows:
function foo() {
// ...
}
foo.prototype.bar = function bar() {
// ...
}
In attempting to do this in TypeScript with an interface, I used the following approach:
interface IFoo {
(): any;
bar(): any;
}
const foo: IFoo = function(): any {
// ...
};
foo.prototype.bar = function bar(): any {
// ...
};
However, I encountered an error:
error TS2322: Type '() => any' is not assignable to type 'IFoo'.
It appears that TypeScript is having trouble during the process of defining foo and its property bar, as foo does not yet have the bar property when assigning it to a const of type IFoo.
How can this issue be resolved?
Put differently, how can I provide an implementation for IFoo?