Create an Interface method that returns the specific class that implements it

I am exploring the creation of an interface that enforces implementing classes to have a method that returns an instance of themselves, preferably statically.

Consider the following interface:

interface MyInterface {
  foo: string;
  getNewInstance(): MyInterface;
}

An example implementation would look like this:

class MyImplementation implements MyInterface {
  foo: string;
  bar: string;

  getNewInstance(): MyInterface {
    return {foo: "test"};
  }
}

However, I am struggling to find a way to mandate that the implementation must return an instance of itself. Additionally, making it static proves to be even more challenging.

In my specific scenario, I am using MyInterface as a generic in

AbstractClass<T extends MyInterface>
, and I aim for MyClass<MyImplementation> to generate a new instance of MyImplementation.

Although I understand there are alternative methods to achieve this, such as requiring the class using the generic to implement it, like so:

AbstractClass<T extends MyInterface> {
  abstract getNewInstance(): T;
}

I still wanted to explore if my initial idea was feasible, as it could streamline the declaration and instance generation. Any insights or suggestions would be greatly appreciated. Thank you.

Answer №1

It is recommended to exclude the getNewInstance method when returning:

interface MyInterface<T> {
    getNewInstance(): Omit<T, 'getNewInstance'>;
}

class MyImplementation implements MyInterface<MyImplementation> {
    foo: string;
    bar: string;
    
    // This will result in an error: Property 'bar' is missing in type '{ foo: string; }'
    getNewInstance() {
        return {foo: "test"};
    }
}

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