Creating a typesafe union type in TypeScript for a form function is a great way to

I am working on a function that can take either a single value or an array of values, and produce new values based on the input. However, the function is unable to determine whether to return a single value or an array based on the type of the input.

How can I make TypeScript understand that the current value being passed to the function is an array, and that the returned values will also be in an array format?

  prepareForResponseMany2(data: ProductEntity | ProductEntity[]): ProductType | ProductType[] {
    if (Array.isArray(data)) {
      return data.map(entity => this.prepareForResponse(entity));
    }

    return this.prepareForResponse(data);
  }

https://i.sstatic.net/m29i8.png

Answer №1

Utilizing function overloading seems to be the solution for achieving your desired outcome. An example of how this can be implemented is by creating an interface as follows:

  prepareForResponseMany2(data: ProductEntity, ): ProductType;
  prepareForResponseMany2(data: ProductEntity[], ): ProductType[];
  prepareForResponseMany2(data: any): ProductType | ProductType[] {
    if (Array.isArray(data)) {
      return data.map(entity => this.prepareForResponse(entity));
    }

    return this.prepareForResponse(data);
  }

With this approach, the type of the returned value will vary based on the type of argument provided to the method.

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