Creating a Typescript interface that has a property which refers to itself as a parameter

One of the unique features of my type is that it includes a property which is a class taking that same type as a parameter.

interface CustomType<P extends {}> {
  name: string;
  props: P;
  field: new(type: CustomType<P>) => { ... };
}

// Defining various Types
interface AllTypes {
  Foo: CustomType<{}>;
  Bar: CustomType<{
    foo: string;
    bar: number
  }>
}
type SpecificType = AllTypes[keyof AllTypes];

I have a function that receives a SpecificType and attempts to create an instance of its field, but it results in an error.

function myFunction(type: SpecificType) {
  return new type.field(type);  // Error
}

To fix this error, I could modify CustomType.field to

new(type: SpecificType) => ...
. However, doing so may lead to additional errors later on.

class SpecialField<T extends SpecificType> {
  type: T;
  constructor(type: T) {
    this.type = type;
  }
}
declare class FooField extends SpecialField<AllTypes['Foo']> {}
declare class BarField extends SpecialField<AllTypes['Bar']> {}

const fields: SpecificType[] = [
  {
    name: 'foo',
    props: {},
    field: FooField,
  },
  {
    name: 'bar',
    props: {  // This error is intentional and expected
      foo: 0,
      bar: 'hello',
    },
    field: BarField,  // Error
  },
];

Answer №1

This appears to be the solution you are searching for:

definition Type<T extends {}> {
  label: string;
  attributes: T;
  method: new<T extends Type<any>>(type: T) => { };
}

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