Creating a Vue TypeScript component and utilizing child methods

One common issue I have encountered is trying to access a method from a child component. It usually works fine, but sometimes additional steps are needed.

this.$refs.searchInput.reset()

To satisfy TypeScript's requirements, you may need to do the following:

(this.$refs.searchInput as HTMLFormElement).reset()

The syntax can be a bit cumbersome at times. Is there a way to simplify this within the component options?

export default Vue.extend({
  name: 'UserForm',
  components: {
       SearchInput as HTMLFORMELEMENT
    }

Consider utilizing the class/decorator syntax to potentially streamline this process.

Answer №1

It is not officially supported to declare the type for $refs in component options.

However, you can bypass the need for type assertion by utilizing either vue-class-component:

import Vue from 'vue'
import Component from 'vue-class-component'

@Component
export default class UserForm extends Vue {
  $refs!: {
    searchInput: HTMLFormElement
  }

  mounted() {
    this.$refs.searchInput.reset()
  }
}

or vue-property-decorator:

import { Vue, Component, Ref } from 'vue-property-decorator'

@Component
export default class UserForm extends Vue {
  @Ref() readonly searchInput!: HTMLFormElement

  mounted() {
    this.searchInput.reset()
  }
}

Alternatively, with the Composition API, specify the type for the template ref:

import { defineComponent, ref, onMounted } from 'vue' // or `@vue/composition-api` for Vue 2

export default defineComponent({
  setup() {
    const searchInput = ref<HTMLFormElement>()

    onMounted(() => searchInput.value?.reset())

    return { searchInput }
  }
})

demo

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