Creating Object of Objects in TypeScript: A Comprehensive Guide

Assuming I have a structure similar to this:

interface Student {
  firstName: string;
  lastName: string;
  year: number;
  id: number;
}

If I intend to handle an array of these structures, I can simply specify the type as Student[].

Instead of utilizing an array, I opt for an object where student IDs serve as keys and students as corresponding values, making look-ups convenient.

let student1: Student;
let student2: Student;
let students = {001: student1, 002: student2 }

Is there a way to represent this data structure as the type passed into or returned from functions?

I could create an interface like this:

interface StudentRecord {
  id: number;
  student: Student
}

However, that doesn't quite align with the desired type. I require a way to indicate that I possess an object containing objects structured in a similar fashion, akin to how Student[] specifies an array filled with similar objects.

Answer №1

To create a more versatile key, consider making the key dynamic:

interface IStudentData {
   [dynamicKey: string]: Student
}

Answer №2

Utilize the predefined Record type:

type EmployeesById = Record<Employee['id'], Employee>;

Answer №3

There are several approaches you can take:

String Index Signature

You can utilize an index signature, as mentioned in @messerbill's response:

interface StudentRecord {
    [P: string]: Student;
}

If you prefer a more cautious approach (see caveat below):

interface StudentRecordSafe {
    [P: string]: Student | undefined;
}

Mapped Type Syntax

Another option is to use the mapped type syntax:

type StudentRecord = {
    [P in string]: Student;
}

For a safer version of this method (see caveat below):

type StudentRecordSafe = {
    [P in String]?: Student
}

This approach is similar to a string index signature but allows for variations like using a union of specific strings. You can also make use of the utility type called Record, defined as follows:

type Record<K extends string, T> = {
    [P in K]: T;
}

Therefore, you could write it as

type StudentRecord = Record<string, Student>
. (Or
type StudentRecordSafe = Partial<Record<string, Student>>
) (Personally, I find using Record easier to understand and implement compared to the longer syntax)

A Caveat with Index Signature and Mapped Type Syntax

An important point to note with both these methods is their optimistic assumption regarding the existence of students for a given id. They assume that every string key corresponds to a valid Student object, even when that may not be true. For instance, the following code compiles successfully for both cases:

const students: StudentRecord = {};
students["badId"].id // Runtime error: cannot read property id of undefind

Comparatively, when using the cautious versions:

const students: StudentRecordSafe = {}
students["badId"].id;  // Compile error, object might be undefined

Although slightly more tedious to work with, especially if you're certain about the existing ids, it does offer better type safety.

With the release of version 4.1, Typescript now includes a flag named noUncheckedIndexedAccess that addresses this issue. With the flag enabled, any accesses to an index signature like this will be considered potentially undefined. This renders the "cautious" version unnecessary if the flag is activated. (Please note that the flag is not automatically included with strict: true and needs to be manually enabled in the tsconfig file)

Map objects

A slight alteration in your code, but you can also opt for a proper Map object, which inherently provides the "safe" version where thorough checks are required before accessing elements:

type StudentMap = Map<string, Student>;
const students: StudentMap = new Map();
students.get("badId").id; // Compiler error, object might be undefined

Answer №4

Instead of creating students as {001: student1, 002: student2 }, you can simplify it to let students = {student1, student2 }. This way, you can easily access them by their index such as students[0] and students[1]. If you need specific information about a student, you can retrieve it like students[0].firstName

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