Creating specific string literals in Angular using TypeScript: a step-by-step guide

I recently created a group of radio buttons for selection:

https://i.sstatic.net/CDM5A.png

<mat-radio-group [(ngModel)]="learningMode" aria-label="Select an learning mode">
    <mat-radio-button value="videos">Videos
            <mat-icon>videocam</mat-icon>
    </mat-radio-button>
    <mat-radio-button value="vocabulary">Vocabulary
            <mat-icon>feed</mat-icon>
    </mat-radio-button>
    <mat-radio-button value="wordSearch">Word Search
            <mat-icon>search</mat-icon>
    </mat-radio-button>
</mat-radio-group>

Everything works perfectly when I set learningMode as a string.

import { Component, OnInit } from '@angular/core';

@Component({
  selector: 'app-home',
  templateUrl: './home.component.html',
  styleUrls: ['./home.component.css']
})
export class HomeComponent {
  learningMode: string = 'videos';
}

The TypeScript Handbook suggests narrowing down the string to a Literal Type with three specific strings:

s: string, alignment: "left" | "right" | "center"

However, my attempt at implementation doesn't seem to be working as expected:

import { Component, OnInit } from '@angular/core';

@Component({
  selector: 'app-home',
  templateUrl: './home.component.html',
  styleUrls: ['./home.component.css']
})
export class HomeComponent {
   learningMode: string, learningModes: 'videos' | 'vocabulary' | 'wordSearch' = 'videos';
}

Any suggestions on how I can properly narrow down learningMode to one of three specific strings?

Answer №1

It seems like my understanding is correct. Here is my approach to narrow down the learning mode.

export declare type LearningModes = 'videos' | 'vocabulary' | 'wordSearch';

Following that, I would include:

 learningMode: LearningModes;

You are unable to use an equals sign in declaring a type. Therefore, there needs to be a method (function) implemented to manage this logic. For instance, utilizing an if-else statement can be one way to handle it.

 example(test: string){
   if (test === 'videos'){
      return 'wordSearch'
    }
  }

Answer №2

Your method of declaring syntax seems to be slightly incorrect.

learningType: 'videos' | 'vocabulary' | 'wordSearch' = 'videos';
//the default value will be set to videos

Answer №3

Below is the detailed solution provided.

import { Component, OnInit } from '@angular/core';

export declare type StudyMethods = 'lectures' | 'flashcards' | 'practiceQuestions';

@Component({
  selector: 'app-landing',
  templateUrl: './landing.component.html',
  styleUrls: ['./landing.component.css']
})
export class LandingComponent implements OnInit {
  studyMethod: StudyMethods;
  
  constructor() { }

  ngOnInit(): void {
    this.studyMethod = 'lectures';
  }

}

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