Creating string unions by combining substrings using template literals

I am looking to streamline the process of deriving a new union from an existing one, without having to explicitly state the string as a parameter each time. The goal is to extract all root strings that end in .bar from a union of translation key strings like this:

type Keys = 'foo.bar' | 'baz.bar' | 'fail.error';

An example desired output for the above union would be 'foo' | 'baz'

My current solution involves using generics to achieve this, but it requires manual input of the string as a parameter:

type Namespace<T extends string = string> = `${T}.bar` extends Keys ? T : never;

const example0: Namespace<'foo'> = 'foo'; // Works, but needs explicit typing
const example1: Namespace<'notFound'> = 'notFound'; // Produces an error as expected

However, I am looking for a more efficient way to define and use this type, where I don't have to specify the string parameter each time:

const example2: Namespace = 'foo'; // Should work without providing the type
const example3: Namespace = 'baz'; // Should also be allowed
const example4: Namespace = 'fail'; // Expected to throw an error
const example5: Namespace = 'notFound'; // Should result in an error

If there is a better approach to achieving this type, I would greatly appreciate any suggestions.

Playground link

Answer №1

In my strategy, I propose the creation of a unique distributive object type (as introduced in a pull request on microsoft/TypeScript#47109). This involves initially constructing a mapped type over Keys, where each key P contains a property that corresponds to the first segment of P if it ends with ".bar", or never otherwise. Subsequently, we use indexed access to retrieve the desired Namespace union type from this object type by using Keys. This process effectively spreads the task of extracting the portion before ".bar" across the union of entries in Keys:

type Namespace = { [P in Keys]: P extends `${infer K}.bar` ? K : never }[Keys];
// type Namespace = "foo" | "baz"

If needed, this approach can be extended to a Prefix<T, U> function, which operates on a union of string literals T and a suffix U, returning the prefix of elements in T followed by the suffix U:

type Prefix<T extends string, U extends string> =
    { [P in T]: P extends `${infer K}${U}` ? K : never }[T];

type AlsoNamespace = Prefix<Keys, ".bar">
// type AlsoNamespace = "foo" | "baz"

For further exploration and testing, you can visit the Playground link here.

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