Is it possible to securely implement two interfaces in Typescript that both have a member of the same name? Can this be achieved?
For example:
interface IFace1 {
name: string;
}
interface IFace2 {
name: string;
}
class SomeClass implements IFace1, IFace2 {
// How can we implement IFace1.name and IFace2.name ??
}
In C#, this issue can be resolved due to its type information at runtime. However, how would Typescript handle this situation?
When it comes to TypeScript, the structural type system means that IFace1 and IFace2 are essentially indistinguishable. Both interfaces can be implemented in the same way:
class SomeClass implements IFace1, IFace2 {
name = 'foo';
}
As pointed out by vcsjones, due to the absence of runtime type information, there is no feasible way for this to function based on nominal distinctions.
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