Determine whether something has the potential to be a string in TypeScript

I am looking to create a TypeScript type that can identify whether an element has the potential to be a string.

This means the element should have the type "string" or "any", but not "number", "boolean", "number[]", "Person", etc.

I have experimented with conditional types, but I am struggling to exclude "anything that cannot be a string".

I also tried using the type Exclude, but it did not achieve exactly what I need.

EDIT

Let me explain my problem more clearly: I am creating a static method foo(data) which will perform a certain action and return a string if the data is a string, or do something else and return a number if the data is not a string.

To achieve this, I can simply use overloads like this:

class FooClass {

    static foo(data: string): string
    static foo(data: any): number
    static foo(data: any): string | number {
        if (typeof data === 'string') {
            return 'a';
        } else {
            return 2;
        }
    }
}

Now, let's consider that the foo() method will throw an Error if the data is not a string. In this case, there are two scenarios:

  • If the user of the method does not know the type of the data (which could be a string), I want them to be able to use the method and I will return an Error if it's not a string.

  • If the user knows the type of the data (e.g., a number), I want to inform them that it is impossible for it to be a string. I want this information to be displayed as an error during type checking in the IDE, not at runtime.

class FooClass {

    static foo(data: string): string
    static foo(data: NotAString): Error
    static foo(data: any): string | Error {
        if (typeof data === 'string') {
            return 'a';
        } else {
            return new Error();
        }
    }
}
let foo1: string;
const bar1: string = FooClass.foo(foo1);  // No error
let foo2: any;
const bar2: string = FooClass.foo(foo2);  // No error
let foo3: number;
const bar3: string = FooClass.foo(foo3);  // Error (displayed on the IDE)
let foo4: Bar;
const bar4: string = FooClass.foo(foo4);  // Error (displayed on the IDE)

I am interested in knowing how to define the type NotAString (or its opposite, CouldBeAString).

Any suggestions?

Thank you!

Answer №1

It appears that there may be some confusion between the type system and functional checks in this context.

If you need to verify at runtime whether something is a string, you would follow the same logic as you would in regular JS.

Runtime check on a property

if (typeof something === 'string') { ... }

When dealing with data obtained from an API or similar source, it is always necessary to utilize code like this, as the type system does not conduct automatic runtime checks.

Conditional type thinning

If you need to create a conditional type that enables you to narrow down the type of a parameter, there are various approaches to consider. One important point to remember is:

  • In current versions of TS, unknown serves as the default type, rather than any
  • unknown and any encompass any valid data types within the language. It is not possible to specify that something is unknown but not number or boolean.
  • Use unknown when unsure about a particular type
  • If certain it is an object but uncertain about its properties, define it as Record<string, unknown>

To narrow down types, a combination of a generic property and the extends keyword can be employed.

type Result<T> = T extends string
  ? A
  : T extends boolean
  ? B
  : T extends number
  ? C
  : never;

Where A, B, C signify result types based on the generic type.

If a generic parameter is not explicitly set, the incoming prop defaults to type unknown. Alternatively, you can limit it to specific values to exert more precise control over your entry parameters.

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