Differentiating between 'TS7030: Not all code paths return a value' and the conflict resolution of ESLint rules 'no-undefined' and 'no-useless return'

Objective

I recognize that ESLint is not the ultimate authority and can be customized differently. However, in this query, I am seeking one of the following outcomes:

  • Resolve the conflict while adhering to all specified rules
  • Be advised to disable the ESLint rule <rule name> because <argumentation> in this specific scenario

Description of Conflict

The code snippet below is valid and functional, but it violates the ESLint rule no-undefined:

@Component
export default class MyComponent extends Vue {

  public static getInstanceByReference(
    vueReference: Vue | Element | Array<Vue> | Array<Element>
  ): MyComponent | undefined {
    if (vueReference instanceof MyComponent) {
      return vueReference;
    }
    return undefined;
  }
}

Removing undefined from return undefined would lead to a violation of the no-useless-return rule:

@Component
export default class MyComponent extends Vue {

  public static getInstanceByReference(
    vueReference: Vue | Element | Array<Vue> | Array<Element>
  ): MyComponent | undefined {
    if (vueReference instanceof MyComponent) {
      return vueReference;
    }
    return;
  }
}

If we eliminate the final return statement which is deemed pointless in terms of JavaScript syntax, it would result in a TypeScript error:

TS7030: Not all code paths return a value.
@Component
export default class MyComponent extends Vue {

  public static getInstanceByReference(
    vueReference: Vue | Element | Array<Vue> | Array<Element>
  ): MyComponent | undefined {
    if (vueReference instanceof MyComponent) {
      return vueReference;
    }
  }
}

Changing the return value signature to MyComponent | void would trigger a violation of the no-invalid-void-type rule within @typescript-eslint.

Answer №1

Have you thought about the objective of your code?

If the aim is to indicate an error or a lack of value, then using a "nullish" value would be appropriate. If your lint settings prohibit the use of the undefined value, why not opt for null instead?

 public static getInstanceByReference(
    vueReference: Vue | Element | Array<Vue> | Array<Element>
  ): MyComponent | null {
    if (vueReference instanceof MyComponent) {
      return vueReference;
    }
    return null;
  }

If you are really keen on having the undefined value without directly stating it, you can utilize the void operator as suggested in the no-undefined documentation:

 public static getInstanceByReference(
    vueReference: Vue | Element | Array<Vue> | Array<Element>
  ): MyComponent | undefined {
    if (vueReference instanceof MyComponent) {
      return vueReference;
    }
    return void 0;
  }

On another note.

If we change the return value signature to MyComponent | void, we get flagged for violating the no-invalid-void-type rule by @typescript-eslint.

Using void in a union type is ill-advised. It doesn't make sense to say "this function returns something or nothing at all". This can lead to counterintuitive behavior in TypeScript, like disabling checks for missing return statements.

The no-invalid-void-type rule highlights instances of MyComponent | void, which likely explains why your lint configuration enforces this rule.

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