Searching for a way to identify matching strings and substrings in an array. For example:
Given a string "3-100" and an array of strings ["3", "3-1", "3-15", "3-",3-10", "3-100"].
When looping through the array, the expected outcomes should be:
"3" -> true,
"3-1" -> false,
"3-15" -> false,
"3-" -> false,
"3-10" -> false,
"3-100" -> true,
What methods can be used achieve this? Previously attempted .includes() which did not work for all cases. Seeking advice.
Best regards, Adjo
Utilizing Regular Expressions
var arr = ["3", "3-1", "3-15", "3-", "3-10", "3-100"];
var reg = /^3(-100)?$/;
var result = arr.reduce((acc, val, ind) => {
acc[ind] = reg.test(val);
return acc;
}, []);
console.log(result);To find specific parts within a string, you can split the string and then use Array#includes.
let text = "2-50",
segments = text.split('-').map((_, index, arr) => arr.slice(0, index + 1).join('-')),
keywords = ["2", "2-3", "2-10", "2-", "2-20", "2-50"],
outcome = keywords.map(term => segments.includes(term));
console.log(outcome);This code snippet demonstrates a backward-compatible solution:
var numbers = ["3", "3-1", "3-15", "3-", "3-10", "3-100"];
var searchA = "3";
var searchB = "100";
for( var i=0; i< numbers.length; i++) {
console.log( numbers[i] + " = " + checkValue(searchA, searchB, numbers[i]))
}
function checkValue( A, B, value ){
var subNumbers = value.split("-");
if( subNumbers[0] != A ) return false;
if( subNumbers.length == 1 ) return true;
if( subNumbers[1] != B ) return false;
return true;
}You can test this code on JS Bin
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