Discovering the Object with the Lowest Key Value in Typescript

Question

Within my TypeScript code, I have defined a List as myList: Package[]. The structure of the Package model is outlined below -

export class Package {
ID: Number;
Price: Number;

}

I am trying to retrieve a Package object with the lowest Price value using the following code snippet:

myList.min(p=>p.Price)

Your guidance on this matter would be greatly appreciated.

Answer 1

Answer №1

One way to accomplish this is by implementing the reduce function:

myList.reduce((result, element) => result.Value < element.Value ? result : element);

Answer 2

One way to accomplish this is by implementing the reduce function:

myList.reduce((result, element) => result.Value < element.Value ? result : element);

Answer 3

If you're looking for a solution, one approach could be to utilize the lodash function minBy in the following manner:

_.minBy(listOfItems, 'Price');

For more information about how to use lodash, refer to their documentation here.

Answer 4

If you're looking for a solution, one approach could be to utilize the lodash function minBy in the following manner:

_.minBy(listOfItems, 'Price');

For more information about how to use lodash, refer to their documentation here.

Answer 5

Understanding the sort method for arrays is straightforward:

[...arr].sort((a, b) => b.p - a.p)[0]

This approach also provides a way to identify objects with both the minimum and maximum values when required.

However, it should be noted that using the reduce method is considered a more efficient and preferable method, as detailed in another answer.

Answer 6

Understanding the sort method for arrays is straightforward:

[...arr].sort((a, b) => b.p - a.p)[0]

This approach also provides a way to identify objects with both the minimum and maximum values when required.

However, it should be noted that using the reduce method is considered a more efficient and preferable method, as detailed in another answer.