Embrace TypeScript's acceptance of types

Consider the TypeScript code snippet below:

type Foo = string | number
    
function f<T extends string>(v : T) {
  (...)
}
    
const v : Foo = "ok"
    
f(v)

The type checker doesn't raise any issues with this code. It seems that even though v is of type Foo and could potentially be a number, in this scenario, it's actually a string being passed to f, so everything works well.

However, the technical mechanism behind this behavior is not entirely clear. We specified that f only accepts a string or its subtypes, yet we are providing it with a variable declared as a Foo.

Answer №1

TypeScript utilizes control flow analysis to automatically narrow down the perceived type of a value to a subtype under specific conditions. This narrowing through control flow analysis is an incredibly valuable feature of TypeScript, as it eliminates the need for manual downcasting or asserting that a value of a certain type actually belongs to a subtype.

You may already be familiar with type guards, such as when you use typeOf checks on variables. For example:

function g(v: Foo) {
  if (typeof v === "string") {
    f(v); // compiles with no error
  }
}

In this case, the compiler recognizes that v has been narrowed from type Foo to just string. Without this analysis, you would have to write f(v as string) even after confirming that v is indeed a string, leaving room for errors if you later change the check to typeof v === "number".

Your code also benefits from narrowing through control flow analysis:


If you have a variable of a union type (like v of type Foo, which is essentially string | number), the type checker will narrow down the apparent type of the variable when you assign a value to the variable that matches one of the union members.

For instance, by assigning const v: Foo = "ok", the compiler narrows v from string | number to just string. Subsequently, the compiler treats v as type string, enabling you to call

f(v)</code without any errors.</p>
<p>Without this analysis, you would have to resort to writing <code>f(v as string)
, which could introduce redundancy and potential bugs if you later changed the assignment to const v: Foo = 123.

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