Enrich TypeScript objects by incorporating additional properties beyond the ones already present

If I have an expression and want to add extra properties without repeating existing ones, how can I achieve that?

For instance, if the expression is a variable, it's simple to include additional fields (like adding field e):

const x = { a: 1 };
const y = x as (typeof x) & { e?: number };

But what if the variable (x) is nested inside an object like this:

f({
    x: { a: 1, b: 1, … }
    // I want type of x to be { a: number; b: number; …; e?: number }, 
    // but without repeating all properties
});

The key is not to have e in the initial object for logic reasons, even as undefined.

Although, assigning x.e later on is necessary.

Answer №1

It seems like you're looking to utilize the spread operator with object literals based on your question. If your variable x is already established, you can achieve this by following this pattern:

const z = { c: 2, d: 3 }

g({
    x: { ...z, f: 5 }
});

Keep in mind that any elements following ...z will overwrite existing values if there is a clash with keys in z.

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